find the area of a square whose diognal length is 3.6.
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if we consider a square of side length x then,
from Pythagoras theorem
2 x² = 3.6²
x = 3.6 / √2
x = 2.55
now area = x²
= 2.55²
= 6.5025
from Pythagoras theorem
2 x² = 3.6²
x = 3.6 / √2
x = 2.55
now area = x²
= 2.55²
= 6.5025
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