Question

find the area of a square whose perimeter is 9 1 /11​

Answer 1

$area \: of \: 4.24 \: m {}^{2}$

Step-by-step explanation:

each side of square =a

then perimeter of =4a

=4a=91/11

=a=2.06 m

$therefore \: area \: \\ a {}^{2} \: \\ (2.06)2 \\ 4.24m {}^{2}$