Question

Find the area of a square whose perimeter is 9whole 1 by 11m Pls ans urgently

Answer 1

$perimeter \: of \: square = 9 \ \frac{1}{11} m = \frac{100}{11} m \\ \\ = > 4 \times side = \frac{100}{11} \\ \\ = > side = \frac{100}{4 \times 11} = \frac{25}{11} m \\ \\ area = (side) {}^{2} = ( \frac{25}{11} ) {}^{2} = \frac{625}{11} \\ \\ = 56 \ \frac{9}{11} m {}^{2}$

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