find the area of a square whose perimeter is equal to the perimeter of a rectangle whose length and breadth is 30 and 20 CM respectively
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Answered by
2
Answer:
Step-by-step explanation:
Perimeter of square = perimeter of rectangle
4side = 2(l+b)
Let side = x
4x = 2(30+20)
4x = 2×50
4x=100
X=100/4=25
Sides of square = 25cm
Area of square = side ²
= (25)² = 625cm²
Hope it works well
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dishabucha:
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Answered by
1
Given
Length=30cm
Breadth=20cm
perimeter of the rectangle=2(l+b)
=2(30+20)
=2(50)
=100 cm
Given that,
Perimeter of a rectangle=perimeter of
square
perimeter of a square=100cm
we can replace the formula,
4*side=100cm
side=100/4cm
side=25cm
then,
Area of square= (side)^2
=(25)^2= 625 cm^2
Hope it helps
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