Question

Find the area of a square whose perimeter is the
same as the perimeter of a rectangle with area 60
cm and breadth 6 cm.​

Answer 1

Answer:

        64cm²

Step-by-step explanation:

Area of rectangle = length × breadth = l × b

60cm² = l × 6cm

l = 60cm² / 6cm

l = 10cm

Perimeter of rectangle = 2 (l + b)

                                      = 2 (10 + 6)

                                      = 2 × 16

                                      = 32cm

Perimeter of rectangle = Perimeter of square = 32cm

Perimeter of square = 4 × length of one side

32 = 4 × l

l = 32 / 4

l = 8 cm

Area of square = (length of one side)² = l²

Area of square = 8²

                         = 8 × 8

                         = 64cm²

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Answer 2

Step-by-step explanation:

${\huge{\bf{\purple{\mathbb{\underline {Formal}}}}}}$

$area \: of \: rectangle = l \times b$

$area \: of \: square = a {}^{2}$

$perimeter \: of \: square \: = 4a$

$perimeter \: = 2(l + b) \:$

${\huge{\bf{\purple{\mathbb{\underline {Question}}}}}}$

Find the area of a square whose perimeter is the

same as the perimeter of a rectangle with area 60cm² and breadth 6 cm.

${\huge{\bf{\purple{\mathbb{\underline {Answer:-}}}}}}$

64cm²

${\huge{\bf{\purple{\mathbb{\underline {Explanation}}}}}}$

area of rectangle= l×b

60=l×6

l=60/6

l=10cm

perimeter of rectangle=perimeter of square=2(l+b) =2(10+6)=2×16=32cm

side of square=32/4= 8cm

area of square=8²=64 cm²