Math, asked by monikak5340, 9 months ago

Find the area of a square whose perimeter si 260.8 m.

Answers

Answered by kvarunkumar1975
1

Answer:

4251.04 m^{2}

Step-by-step explanation:

Perimeter of a square of side a is 4a

Therefore 4a = 260.8

a = 65.2

Area of the square = a^{2} = 65.2 * 65.2 = 4251.04 m^{2}

Answered by rishikasingh91
0

Answer:

The answer is 4251.04

Step-by-step explanation:

Perimeter of square is 4a

So, therefore 4a = 260.8

a= 65.2

Area of square = a×a = 65.2 ×65.2 = 4251.04

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