find the area of a square whose side is (2x-y) unit??
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Answer:
The area of rectangle=a×b=(2x+3y)(3x+2y)=(6x
2
+6y
2
+13xy)
area of square =a
2
=(x+y)
2
=(x
2
+y
2
+2xy)
therefore remaining area is equal to area of rectangle−area of square=(6x
2
+6y
2
+13xy)−(x
2
+y
2
+2xy)=(5x
2
+5y
2
+11xy)
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