Question

Find the area of a square whose side is 3x²-y

Answer 1

Step-by-step explanation:

Given:-

a square's side=${3x}^{2}-y$

To find:-

Area of the square

Solution:-

As we know in a square

${\boxed{{3x}^{2}-y}}$

$according \: to \: the \: formula \\ \\ area = { ({3x}^{2} - y)}^{2} \\ = ({3x}^{2} ) {}^{2} - 2 \times {3x}^{2} \times y + {y}^{2} \\ = {3x}^{4} - {6x}^{2} y + {y}^{2} \\ = {3x}^{2} ( {3x}^{2} - 2y) + {y}^{2} \\ = ( {3x}^{2} + {y}^{2} )( {3x}^{2} - 2y)$