find the area of a square whose side is 4.8cm
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Answered by
1
Answer:
AMPLITUDE -- THE MAXIMUM DISPLACEMENT OF A VIBRATING OBJECT FROM ITS CENTRAL POSITION.....
Frequency -- the number of oscillation per second........
Time period.-- the time taken by A vibrating ( oscillating ) object to complete one vibration....
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Answered by
5
Answer:
area =side×side
=4.8 ×4.8
area of the square =23.04cm
hope this helps
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