Question

find the area of a square whose side is 4.8cm​

Answer 1

Answer:

AMPLITUDE -- THE MAXIMUM DISPLACEMENT OF A VIBRATING OBJECT FROM ITS CENTRAL POSITION.....

Frequency -- the number of oscillation per second........

Time period.-- the time taken by A vibrating ( oscillating ) object to complete one vibration....

Hope it helps you....✌️✌️

Answer 2

Answer:

area =side×side

=4.8 ×4.8

area of the square =23.04cm

hope this helps