Question

find the area of a square whose side is 5cm​

Answer 1

$\sf\red{Solution:-}$

Area of a square = (side²) square units

Given measure of the sq's side = 5 cm

So, required area = (5²) cm²

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ = 25 cm²

$\sf\red{Extra \: info:-}$

• Perimeter of square = (4×side) units
• Area of square = (side²) sq units
• Perimeter of rect =2(l+b) units
• Area of rect = (l×b) sq units
• Perimeter of Δ = (3×side) units
• Area of Δ = (1/2 × base × height) sq units

Thank you !

Answer 2

Answer:

Hence the area of a square is $25\:cm^{2}$

Step-by-step explanation:

According to the question details are as below,

The given detail are side of a square is 5cm,

We have to find the area of a square,

Here we have to use the formula of area of a square,

Area is equal to side square, i.e.$A=a^{2}$

Where a is the side of the square,

Given a= 5 cm,

Substitute the value in the formula of area of a square, we get

$A=5^{2}$

Squaring a number is to multiply the number by itself we get,

$A=5\times5\\A=25\:cm^{2}$

Hence the area of a square is $25\:cm^{2}$