Math, asked by ShiraSenpai, 5 months ago

Find the area of a square whose side is x + 8. Please add a solution.

Answers

Answered by praneethaeati
2

Answer:

area of square is s^2 therefore,(x+8)^2=x^2+64+16x

Answered by TahooraFatima
1

Answer:

area of square=side × side

x+8×x+8

(x+8)^2

{(a+b)^2=a^2+2ab+b^2

x^2+2×x×8+8^2

x^2+16x+64

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