Find the area of a square whose side is x + 8. Please add a solution.
Answers
Answered by
2
Answer:
area of square is s^2 therefore,(x+8)^2=x^2+64+16x
Answered by
1
Answer:
area of square=side × side
x+8×x+8
(x+8)^2
{(a+b)^2=a^2+2ab+b^2
x^2+2×x×8+8^2
x^2+16x+64
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