Question

Find the area of a trapazium where parallel sides are of20m and 8m and the distance between there two sides are 12cm

Answer 1

Answer:

Area of trapezium=168 m²

Step-by-step explanation:

area of trapezium=1/2*height(a+b)

area of trapezium=1/2*12(20+8)

area of trapezium=6(28)                              

Important: do cancellation if possible

area of trapezium=168 m²

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Area\:of\:trapezium=168\:m^{2}}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green {\underline \bold{Given : }} \\ \tt: \implies Length \: of \: || \: sides = 20 \: m \: and \: 8 \: m \\ \\ \tt: \implies Distance \: between \: || \: sides(h) = 12 \\ \\ \red {\underline \bold{To \: Find : }} \\ \tt: \implies Area \: of \: trapezium = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies Area \: of \: trapezium = \frac{1}{2} (sum \: of \: || \: sides)h \\ \\ \tt: \implies Area \: of \: trapezium = \frac{1}{2} (20 + 8) \times 12 \\ \\ \tt: \implies Area \: of \: trapezium = \frac{1}{2} \times 28 \times 12 \\ \\ \tt: \implies Area \: of \: trapezium = 28 \times 6 \\ \\ \green{\tt: \implies Area \: of \: trapezium = 168 \: {m}^{2} }$