Question

find the area of a traperium whose parallel sides are 24 cm and 20 cm and the distance between them is 15 cm​

Answer 1

We know that the length of the parallel sides is 24cm and 20cm and height (h)=15cm

By using the formula Area of trapezium =1/2×(sum of parallel side)×height we get,

=1/2×(24+20)×15

=33 cm^2

Answer 2

Answer:

330 cm²

Step-by-step explanation:

Area of trapezium = $\frac{1}{2}h(a+b)$

h = 15 cm

a = 24cm

b = 20 cm

Misc - a∥b = 24cm ∥ 20cm

$\frac{1}{2}*15*(24+20) = \frac{1}{2} * 15 * 44$

                           $= 15*22 = 330$ (we have cancelled 2 and 44)

Therefore, the answer is 330 cm²

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