Question

find the area of a trapezium if lengths of the two parallel sides are 8.5cm and 11.5cm respectively and its height is 6.2cm​

Answer 1

Answer:

• 62 cm²

Step-by-step explanation:

Given

• Two parallel sides of trapezium :

1. 8.5 cm
2. 11.5 cm

• Height of trapezium = 6.2 cm

To find

• Area of trapezium

Solution

∅ Area of trapezium = a + b / 2 × h

Where :

• a - parallel side 1
• b - parallel side 2
• h - height

Substituting we get :

• (8.5 + 11.5/2) × 6.2
• (20/2) × 6.2
• (10) × 6.2
• 62

Hence, the area of trapezium is 62 cm².

Answer 2

Answer:

$\large{\underline{\underline{\textbf{Given}}}}$

• ~The lengths of two parallel sides of trapezium are 8.5cm and 11.5cm
• ~The height of Trapezium is 6.2 cm

$\large{\underline{\underline{\textbf{To\:Find }}}}$

• ~Area of Trapezium

$\large{\underline{\underline{\textbf{Using Formula}}}}$

$\circ\underline{ \boxed{\sf{ \dfrac{1}{2} \times (sum \: of \: parallel \: sides) × h}}}$

$\large{\underline{\underline{\textbf{Solution}}}}$

${ : \implies \sf{ \dfrac{1}{2} \times (sum \: of \: parallel \: sides) × h}}$

$\begin{gathered} \\ \end{gathered}$

• Substituting the values

$\begin{gathered} \\ \end{gathered}$

${ : \implies \sf{ \dfrac{1}{2} \times (8.5 + 11.5)× 6.2}}$

$\begin{gathered} \\ \end{gathered}$

${ : \implies \sf{ \dfrac{20}{2} × 6.2}}$

$\begin{gathered} \\ \end{gathered}$

${ : \implies \sf{ \cancel\dfrac{20}{2} × 6.2}}$

$\begin{gathered} \\ \end{gathered}$

${ : \implies \sf{ 10× 6.2}}$

$\begin{gathered} \\ \end{gathered}$

${ :\implies\bf{ 62 \: {cm}^{2}}}$

$\begin{gathered} \\ \end{gathered}$

$\begin{gathered} \large \purple\bigstar\underline{ \boxed {\sf \pink{\pmb {62 \: {cm}^{2}}}}} \end{gathered}$

• ~Henceforth,The Area of Trapezium is 62 cm².

$\begin{gathered} \\ \end{gathered}$

$\large{\underline{\underline{\textbf{Know\: More}}}}$

• ➟ Volume of cylinder = πr²h
• ➟ T.S.A of cylinder = 2πrh + 2πr²
• ➟ Volume of cone = ⅓ πr²h
• ➟ C.S.A of cone = πrl
• ➟ T.S.A of cone = πrl + πr²
• ➟ Volume of cuboid = l × b × h
• ➟ C.S.A of cuboid = 2(l + b)h
• ➟ T.S.A of cuboid = 2(lb + bh + lh)
• ➟ C.S.A of cube = 4a²
• ➟ T.S.A of cube = 6a²
• ➟ Volume of cube = a³
• ➟ Volume of sphere = (4/3)πr³
• ➟ Surface area of sphere = 4πr²
• ➟ Volume of hemisphere = ⅔ πr³
• ➟ C.S.A of hemisphere = 2πr²
• ➟ T.S.A of hemisphere = 3πr²