Question

find the area of a trapezium if the length of it's two bases is 8.8 m and 12.9 m respectively and the prependicular distance between two bases is 12 m.​

Answer 1

Given :

• Length of two bases/parallel sides is 8.8 m and 12.9 m .
• Height is 12 m .

To Find :

• Area of Trapezium .

Solution :

$\longmapsto\tt{Parallel\:sides=8.8\:m\:and\:12.9\:m}$

$\longmapsto\tt{Height=12\:m}$

Using Formula :

$\longmapsto\tt\boxed{Area\:of\:Trapezium=\dfrac{1}{2}\times{(Sum\:of\:parallel\:sides)}\times{h}}$

Putting Values :

$\longmapsto\tt{\dfrac{1}{{\cancel{2}}}\times{(8.8+12.9)}\times{{\cancel{12}}}}$

$\longmapsto\tt{21.7\times{6}}$

$\longmapsto\tt\bf{130.2\:{cm}^{2}}$

So , The Area of Trapezium is 130.2 cm² .

Answer 2

Given : Length of the two parallel sides of Trapezium are 8.8 m and 12.9 m . Perpendicular distance between the two bases is 12 cm .

To Find : Find the Area of Trapezium

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SolutioN : For finding the area of this Trapezium we need to apply the formula first . Let's Solve :

$\maltese$ Formula Used :

• ${\underline{\boxed{\pmb{\sf{ Area{\small_{(Trapezium)}} = \dfrac{1}{2} \times \bigg( a + b \bigg) \times Height }}}}}$

Where :

• a = First Parallel Side
• b = Second Parallel Side

$\maltese$ Calculating the Area :

${\dashrightarrow{\qquad{\sf{ Area = \dfrac{1}{2} \times \bigg( a + b \bigg) \times Height }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ Area = \dfrac{1}{2} \times \bigg( 8.8 + 12.9 \bigg) \times 12 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ Area = \dfrac{1}{2} \times 21.7 \times 12 }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ Area = \dfrac{1}{\cancel2} \times \cancel{260.4} }}}} \\ \\ \\ \ {\dashrightarrow{\qquad{\sf{ Area = 1 \times 130.2 }}}} \\ \\ \\ \ {\qquad \; \; \; {\dashrightarrow{\underline{\boxed{\pmb{\sf{ Area = 130.2 \; {m}^{2} }}}}}}} \; {\red{\bigstar}}$

$\therefore \; \;$ Area of the Trapezium is 130.2 m² .

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