Question

Find the area of a trapezium,in which the parallel sides AB=9cm, DC=7cm and the distance

between the parallel sides equals 5cm​

Answer 1

Step-by-step explanation:

area of trapezium=1/2*(9+7)*5

=1/2*16*5=8*5=40cm2

Answer 2

➤ Given:

A trapezium with

• AB (1st side - a) = 9 cm
• DC (2nd side - b) = 7 cm
• Distance between the parallel sides (height - h) = 5 cm

➤ What To Find:

We have to find the area of the trapezium.

➤ Formula For Finding:

$\boxed{ \maltese \: \tt{Area \: of \: Trapezium = \dfrac{a + b}{2} \times h}}$

➤ Solution:

Using the formula,

$\Longrightarrow \rm{Area \: of \: Trapezium = \dfrac{a + b}{2} \times h}$

Substitute the values,

$\Longrightarrow \rm{Area \: of \: Trapezium = \dfrac{9 \: cm + 7 \: cm}{2} \times 5 \: cm}$

Add the numerator,

$\Longrightarrow \rm{Area \: of \: Trapezium = \dfrac{16}{2} \times 5 \: }$

Cancel 16 and 2,

$\Longrightarrow \rm{Area \: of \: Trapezium = 8 \times 5 \: }$

Multiply 8 by 5,

$\Longrightarrow \rm{Area \: of \: Trapezium = 40 \: cm}$

∴ Therefore, the area of the trapezium is 40 cm.