Question

Find the area of a trapezium,lengths of whose parallel sides are 13 cm and 11 cm and the distance between them is 14 cm: (explain in detail)​ with formula​

Answer 1

Answer:

168cm

Step-by-step explanation:

Let the length of the parallel sides be, $b_{1}$  = 13cm and $b_{2}$ = 11cm

h =14cm

therefore, area of trapezium

$=\frac{(b_{1} + b_{2}) ({h}) }{2} \\= \frac{(13 + 11) X (14)}{2} \\=\frac{24 X 14}{2} = \frac{336}{2} =168$

Answer 2

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Given:

• Length of parallel sides = 13cm & 11cm
• Height = 14cm

To Find:

• Area of trapezium

Solution:

$\setlength{\unitlength}{1.5cm}\begin{picture}\thicklines\qbezier(0,0)(0,0)(1,2.2)\qbezier(0,0)(0,0)(4,0)\qbezier(3,2.2)(4,0)(4,0)\qbezier(1.5,2.2)(0,2.2)(3,2.2)\put(0.8,2.4){ \bf A }\put(3,2.4){ \bf D }\put(-0.3,-0.3){ \bf B }\put(4,-0.3){ \bf C }\put(4.4,0){\vector(0,0){2.2}}\put( 4.4, 0){\vector(0,-1){0.1}}\put(4.6,1){ \bf 14\ cm }\put(0, -0.5){\vector(1,0){4}}\put(0, -0.5){\vector( - 1, 0){0.1}}\put(1.7, - 0.9){ \bf 13\ cm }\put(0.8, 2.8){\vector(1,0){2.5}}\put(0.8, 2.8){\vector( - 1, 0){0.1}}\put(1.7, 3){ \bf 11\ cm }\end{picture}$

$\text{We know that,}\\\longrightarrow</p><p>Area\: of \:a \:trapezium = \dfrac{1}{2} * (sum\:of\:parallel\:sides) * height. \\So,\\\implies Area\: of \:the\:trapezium = \dfrac{1}{2\!\!\!\!/_{_1}} * (11+13) * 14\!\!\!\!/^{^7} \\\implies Area\: of \:the\:trapezium = 24 * 7 \\\bf{\impliesArea\: of \:the\:trapezium = 168cm^2}$

Hope it helps!