Find the area of a trapezium, the lengths
of whose parallel sides are 60 cm and
80 cm and the distance between these sides
is 25 cm.
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Answered by
0
Area=1/2×(sum of parallel sides)×distance
=1/2×(60+80)×25 cm²
=1/2×140×25 cm²
=70×25 cm²
=1750cm²
Answered by
1
Answer :
1750 cm²
Explanation :
area of trapezium
1 / 2 ( sum of parallel sides ) × height
= 1 / 2 ( 80 + 60 ) × 25 cm
= 1 /2 ( 140 ) × 25cm
= 70 × 25
= 1750 cm²
Therefore , the area of trapezium is 1750 cm²
Hope it helps :) ❤
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