Question

Find the area of a trapezium,the lengths of whose parallel sides are 60 cm and 80 cm and the distance between these sides is 25 cm

Answer 1

$area \: of \: trapezium \\ = \frac{1}{2} h(a + b)$
height is 25cm
two parellal sides are 60cm and 80 cm

therefore,
$area = \frac{1}{2} 25(60 + 80)$
$= \frac{1}{2} \times 25 \times 140$
$= 1750 {cm}^{2}$

Answer 2

OK so you know a trapezium.
given things are 60and 80 are the parallel sides of trapezium.
and 25 is the distance between.
so distance between means actually the height of trapezium.
so you know the formula to calculate area of trapezium i. e. ½ *(sum of the length of parallel sides) *height. OK.
then so
=1/2*(60+80)*25
=1/2*140*25
=1750 sq. cm

and here you go
the area of trapezium is 1750 sq. cm.

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