Question

find the area of a trapezium where parallel sides are of 20m and 8m and the distance between there two sides are 12cm.​

Answer 1

Given:-

• Parallel sides of a trapezium are 20 m and 8 m.
• Distance between there two sides are 12 cm.

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To find:-

• Area of a trapezium.

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Solution:-

Here,

• Parallel sides = 20 m and 8 m
• Distance between the two sides = 12 cm

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According to the question

★Formula used:-

Area of trapezium = 1/2(a+b)h

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→ a = 20m

→ a = 2000 cm

→ b = 8 m

→ b = 800 cm

→ h = 12 cm

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Now,

→ 1/2 (2000+800)12

→ 6 × 2800

→ 16800 cm²

→ 168 m²

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Here,

• the area of a trapezium is 168 m².

Answer 2

Given :-

• Parallel sides of trapezium = 20 m , 8m
• Distance b/w sides = 12 cm

To Find :-

• Area of this Trapezium

Solution :-

→ Here , the distance between the parallel sides ( height ) of the trapezium is given in cm . So , let's convert other measures given to us in cm

$\star\: \boxed{\sf{\blue{ 1\;m = 100\;cm }}}$

• 8 m = 800 m
• 20 m = 2000 m

→ Now , let's find out the area of this trapezium .

$\underline{\bf{\dag} \:\mathfrak{As\;we\;know\: that\: :}}$

$\star\: \boxed{\sf{\blue{ Area\;of\;Trapezium\;=\dfrac{1}{2}\times(a+b)\times h }}}$

Where ,

a , b = parallel sides

h = height ( distance )

$\sf \implies \dfrac{1}{2} \times (2000+800) \times 12$

$\sf \implies 2800 \times 6$

$\sf \implies 16800 \; cm^{2}$

$\sf \implies 168\;m^{2}$

∴ Area of the trapezium is 168 m²

More to know :-

➝ Area of square = Side × Side

➝ Area of Rectangle = Length × Breadth

➝ Area of Triangle = 1/2 × Base × Height

➝ Area of Rhombus = 1/2 × Product of Diagonals

➝ Area of Circle = πr²

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