Question

Find the area of a trapezium whose length of the parallel sides are 8 cm and 7 cm and its height is 6 cm.

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Answer 1

Answer:

= 45

Step-by-step explanation:

Area = a+b/2 * h

=(8+7) × 6 /2  

= 45

Answer 2

$\large{ \sf\underline{Solution- }}$

Here it is given that,

• Length of parallel sides of trapezium are 8 cm and 7 cm and it's height is 6 cm.

➢ We have to find it's area.

We know,

$\sf \boxed{ \rm Area \: of \: trapezium = \tt\dfrac{1}{2} \: \big(a + b \big) \: h}$

Here,

• a and b are parallel sides of trapezium.
• h stands for height.

$\sf \implies \:{ \rm \tt\dfrac{1}{2} \: \big(8 + 7\big) \: 6}$

$\sf \implies \:{ \rm \tt\dfrac{1}{2} \: \big(15\big) \: 6}$

$\sf \implies \:{ \rm \tt\dfrac{1}{2} \times 90}$

$\sf \implies \:{ \rm \tt \: 45 \: cm^{2} }$

Therefore,

• Area of trapezium = 45 cm²

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More To Know :

⟹ Area of rectangle = Length × Breadth

⟹ Area of square = Side²

⟹ Area of parallelogram = Base × Height

$\rm \implies Area \:of \:rhombus \sf \: = \:{ \rm \dfrac{1}{2} \:\times \: product \:of\: diagonals}$