Question

Find the area of a trapezium whose Paralle sides
are 28.7 cm and 22.3cm and the distance between
them is 16cm.​

Answer 1

Question:-

Find the area of a trapezium whose Paralle sides

are 28.7 cm and 22.3cm and the distance between

them is 16cm.

Answer:-

• The area of trapezium is 408 cm².

To find:-

• Area of trapezium

Solution:-

$\pink{ \boxed{ \pink{ \underline{ \underline{ \mathfrak{ \large{ \green{area = \frac{sum \: of \: parallel \: sides}{2} \times h}}}}}}}}$

• One parallel side = 28.7 cm
• Another parallel side = 22.3 cm
• Height = 16 cm

$\large{ \tt : \implies \: \: \: \:area = \frac{28.7 + 22.3}{2} \times 16}$

$\large{ \tt : \implies \: \: \: \:area = \frac{51}{ \cancel2} \times \cancel16}$

$\large{ \tt : \implies \: \: \: \:area = 51 \times 8}$

$\large{ \tt : \implies \: \: \: \:area = 408 \: {cm}^{2} }$

• The area of trapezium is 408 cm².

Answer 2

$\huge\underline{\bf{Given}}$

• First parallel side = 28.7 cm
• Second parallel side = 22.3 cm
• Height = 16 cm

⠀

$\huge\underline{\bf{To\: find}}$

• Area of the Trapezium.

⠀

$\huge\underline{\bf{Figure}}$

⠀

$\setlength{\unitlength}{1.5cm}\begin{picture}\thicklines\qbezier(0,0)(0,0)(1,2.2)\qbezier(0,0)(0,0)(4,0)\qbezier(3,2.2)(4,0)(4,0)\qbezier(1.5,2.2)(0,2.2)(3,2.2)\put(0.8,2.4){ \bf A }\put(3,2.4){ \bf D }\put(-0.3,-0.3){ \bf B }\put(4,-0.3){ \bf C }\put(4.4,0){\vector(0,0){2.2}}\put( 4.4, 0){\vector(0,-1){0.1}}\put(4.6,1){ \bf 16\ cm }\put(0, -0.5){\vector(1,0){4}}\put(0, -0.5){\vector( - 1, 0){0.1}}\put(1.7, - 0.9){ \bf 28.7\ cm }\put(0.8, 2.8){\vector(1,0){2.5}}\put(0.8, 2.8){\vector( - 1, 0){0.1}}\put(1.7, 3){ \bf 22.3\ cm }\end{picture}$

⠀

$\huge\underline{\bf{Solution}}$

• By using the formula of Area of trapezium, we can solve this question.

⠀

$\boxed{\tt{\bigstar{Area\: of\: trapezium = \dfrac{Sum\: of\: parallel\: sides}{2} \times height{\bigstar}}}}$

⠀

★ Putting the values

$\tt:\implies\: \: \: \: \: \: \: \: {Area = \dfrac{22.3 + 28.7}{2} \times 16}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {Area = \dfrac{51}{\cancel{2}} \times \cancel{16}}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {Area = 51 \times 8}$

⠀

$\tt:\implies\: \: \: \: \: \: \: \: {Area = 408}$

⠀

Hence, area of the Trapezium is 408 cm².

━━━━━━━━━━━━━━━━━━━━━━

⠀

$\huge\underline{\bf{Understanding}}$

✈ To understand the concept clearly, you can go through the figure.

✈ If you are not able to see the figure, go through this link ↓↓

[ https://brainly.in/question/29499429 ]

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬