Question

Find the area of a trapezium whose parallel side are of length 16 DM and 22dm and whose height is 15 DM.​

Answer 1

Given :-

• parallel sides of the trapezium = 16 Dm and 22 Dm
• Height of the trapezium = 15 Dm

To Find :-

• area of the trapezium ?

Solution :-

we know that,

if the parallel sides of the trapezium are ‘a’ and ‘b’ & height is ‘h’

$\boxed{ \bold{area \: of \: trapezium = \frac{1}{2} (a + b) \times h}}$

$\bold{: \implies \frac{1}{2} (16 + 22) \times15 } \\ \\ \bold{: \implies \frac{1}{ \cancel2} \times \cancel{ 38} \times 15} \: \: \: \: \: \: \: \\ \\ \bold{ : \implies 19 \times 15} \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \bold{: \implies285 \: {Dm}^{2} } \: \: \: \: \: \: \: \: \: \: \: \: \:$

hence, the area of the trapezium is 285 Dm²

Answer 2

Answer :

• The area of trapezium is 285 dm².

Step-by-step explanation ::

To Find :-

• The area of trapezium

Solution :-

Given that,

• The length of the two parallel sides of trapezium are 16dm and 22dm
• The height is 15dm

As we know that,

Area of trapezium = 1/2 × ( a + b ) × h

Where,

• a and b are the two parallel sides of trapezium
• h is the height of trapezium

According the question,

=> Area of trapezium = 1/2 × ( 16 + 22 ) × 15

=> Area = 1/2 × 38 × 15

=> Area = 19 × 15

=> Area = 285

∴ The area of trapezium is 285 dm².

Now, Verification

=> 285 = 1/2 × ( 16 + 22 ) × 15

=> 285 = 1/2 × 38 × 15

=> 285 = 1 × 19 × 15

=> 285 = 19 × 15

=> 285 = 285

L.H.S = R.H.S

Hence, Verified !