Question

Find the area of a trapezium whose parallel side is 22cm and 8cm and distant between them is 10cm

Answer 1

Step-by-step explanation:

Formula:

Ar(Trapezium) =

$\frac{a + b}{2} \times \: h$

where a and b are diagonals of the trapezium and h is the height of the trapezium.

Now,

a = 8cm

b = 22cm

h = 10cm (because distance between them is the height)

Substituting it in the formula,

Ar(Trapezium) = (8 + 22) / 2 × 10

= 30/2 × 10

= 15 × 10

= 150 sq.cm

Answer 2

Answer:

150 cm

Step-by-step explanation:

A - 22 cm

B - 8 cm

H - 10 cm

Area of trapezium = 1/2 (a+b)× h

= 1/2 (22+8)×10

=30/2×10

=15×10

ans = 150 cm^2