Question

Find the area of a trapezium whose parallel sides are 10 cm and 7 cm respectively and the distance between them is 6 cm.
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Answer 1

Answer:

$h \times \frac{1}{2} (x + y) \\ \\ \\ \frac{1}{2} \times 6 \times (10 + 7) \\ \\ \\ 3 \times 17 \\ \\ \\ \\ \\ \\ \\ 51 \: \: cm {}^{2}$

Answer 2

Answer:

a= 10cm

b= 7cm

height= 6cm

NOW,

AREA OF TRAPEZIUM = 1/2×h(a+b)

= 1/2×6(10+7)

= 3(17)

=51cm² (ANSWER)

NOTE:

(a+b) ARE THE SUM OF PARALLEL SIDES....

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