Question

Find the area of a trapezium whose parallel sides are 11 cm and 14 cm and height is 10 cm.​

Answer 1

Explanation:

Area = h(a+b) / 2

= 10 (11+ 14) / 2

= 110 + 140 / 2

= 250 /2

= 125 cm^2

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Answer 2

SOLUTION:-

Given:

In a trapezium,

•Parallel sides are 11cm & 14cm.

•Height =10cm

To find:

Area of trapezium.

So,

We know that, formula of the area of trapezium;

$= > \frac{1}{2} \times sum \: of \: parallel \: sides \: \times height$

Therefore,

$= > \frac{1}{2} \times (11 + 14) \times 10 \\ \\ = > \frac{1}{2} \times (25) \times 10 \\ \\ = > 25 \times 5 \\ \\ = > 125 {cm}^{2}$

Thus,

The area of trapezium is 125cm².

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