Question

Find the area of a trapezium whose parallel sides are 12 cm and 20 cm and the distance between
them is 15 cm.

Answer 1

Step-by-step explanation:

area of a trapezium = 1/2 × sum of its parallel sides × distance between them

=>1/2(12+20)(15)

=>1/2(32)(15)

=>16(15)

=>240 cm²

Answer 2

Area of trapezium=

Sum of parallel sides× Height÷2

$\red {distance \: btw. \: 2 \: parallel}$$\red{ sides \: = height}$

Area of trapezium:-

$=>\frac{12 + 20}{2} \times 15 \\ => \frac{32}{2} \times 16 \\ =>11 \times 15 \\=> 240 {cm}^{2}$

$\orange{\tt{Area\: of\: trapezium=240sqcm}}$

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