Question

find the area of a trapezium whose parallel sides are 20 cm and 18 cm long and the distance between them is 15 cm.

Answer 1

Hey mate!!

Area of trapezium =1/2 ×(sumof parallel sides) ×(distance between them )

so

A/Q

$\frac{1}{2} (20 + 18) \times (15) \\ = \frac{38}{2} \times 15 \\ = 19 \times 15 \\ = 285 {cm}^{2}$

Answer 2

The area of the given trapezium will be 285 cm².

Given,

Parallel sides of a trapezium are:

20 cm and 18 cm,

distance between them = 15 cm.

To find,

Area of the given trapezium.

Solution,

Consider a trapezium whose parallel sides are, let $a$ and $b$, and the distance between these two sides is $h$.

Then, the area of this trapezium is given by

$A=(\frac{a+b}{2}) h \hfill ...(1)$

For the given trapezium, sides are,

$a$ = 20 cm,

$b$ = 18 cm, and

$h$ = 15 cm.

So, using eq. (1), the area of the given trapezium will be,

$A=(\frac{20+18}{2} ) \times 15$

$\implies A=(\frac{38}{2} ) \times 15$

$\implies A=19\times 15$

⇒ A = 285 cm².

Therefore, the area of the given trapezium will be 285 cm².

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