Question

Find the area of a trapezium whose parallel sides are 24 cm and 20 cm and the distance between them is 15 cm. 

Answer 1

Area of trapezium =
1/2 (sum of parallel sides) * h

= 1/2 * (24 + 20) * 15
= 1/2 * 44 * 15
= 330 cm2


Hope it helps
Thanks..

Answer 2

Hello!
Here is your answer

Given
Parallel sides
24 cm and 20 cm

Height = distance between them = 15 cm

Formula =
$\frac{1}{2} \times sum \: of \: parallel \: sides \: \times height$
$= \frac{1}{2} \times (24 + 20) \times 15$
$\frac{1}{2} \times 44 \times 15$
$22 \times 15$
$= 330cm$