find the area of a trapezium whose parallel sides are 25cm,13cm and the non parallel sides are 15cm each
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Since both non parallel sides are equal, therefore, the trapezium is isosceles.
Therefore, we draw two lines such that they are form a right angle.
Using pythogotas theorem,
we get (height^2)=(15*15)-(6*6)
height = √225-36
h=√189
h=17cm
Area=1/2*(sum of parallel sides)*height
a=1/2*(25+13)*17
a=323cm²
Therefore, we draw two lines such that they are form a right angle.
Using pythogotas theorem,
we get (height^2)=(15*15)-(6*6)
height = √225-36
h=√189
h=17cm
Area=1/2*(sum of parallel sides)*height
a=1/2*(25+13)*17
a=323cm²
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