Question

Find the area of a trapezium whose parallel sides are 32 cm and 27 cm, and the distance between them is 15 cm.
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Answer 1

Answer:

This is the formula so please use it. A. = a+b height

2

a = base = 32

b = base = 27

h =height. = 15

AREA = 442.5cm2

by using the formula

Answer 2

Step-by-step explanation:

Given :-

Parallel sides of trapezium = 32 cm & 27 cm

Distance between them = 15 cm

To Find :-

Area

Solution :-

We know that

[Area of trapezium = ½ × (sum of parallel sides) × Distance b/w them

$\sf : \implies \: Area = \dfrac{1}{2} \times (32 + 27) \times 15$

$\sf : \implies Area \: = \dfrac{ 1}{2} \times 59 \times 15$

$\sf : \implies Area \: = 59 \times 7.5$

${ \large{ \boxed{ \underline{ \underline{ \pink{ \frak {Area = 442.5 \: {cm}^{2} }}}}}}} \bigstar$

Therefore,

Area of trapezium is 442.5 cm²