Question

Find the area of a trapezium whose parallel sides are 4cm and 5cm and shortest distance between them is 2cm.​

Answer 1

we know that area of trapezium = 1/2×( sum of parallel sides ) × and distance between them

= 1/2×(4cm+5cm)×2cm

= 1/2×9cm×2cm

=9cm

Answer 2

Given :

⬤ Parallel Sides of Trapezium are 4 cm and 5 cm .

⬤ Height of Trapezium is 2 cm.

To Find :

⬤ Area of Trapezium .

Formula Used :

$\bf[\:{Area\:of\: Trapezium=\dfrac{1}{2}\times{(Sum\:of\:Parallel\:Side)}\times{h}}\:]$

• h = height

Solution :

• Parallel Sides = 4 cm , 5 cm .
• Height = 2 cm .

According to the Formula :-

1/2 × (4 + 5) × 2

4 + 5

9

Therefore , The Area of Trapezium is 9 cm² .

═════════════════════════

Related Formulas :

• Area of Trapezium = ½ × (Sum of Parallel Sides) × h
• Area of Rectangle = l × b
• Area of Square = Side × Side
• Area of Parallelogram = b × h
• Area of Triangle = 1/2 × b × h
• Area of Circle = πr²

═════════════════════════