find the area of a trapezium whose parallel sides are 57 cm and 33 cm and the distance between them is 13 cm
vivekkumar8:
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Answers
Answered by
220
Sum of Parallel sides = 57+33 = 90 cm
Height = 13 cm
Area = 1/2 x sum of parallel sides × height
Area = 1/2 x 90 × 13 ====== 45×13 = 585 sq cm
Height = 13 cm
Area = 1/2 x sum of parallel sides × height
Area = 1/2 x 90 × 13 ====== 45×13 = 585 sq cm
Answered by
59
Area of Trapezium= 1/2 x (sum of the parallel sides) x distance between them
= 1/2 x (130) x 13
=1 x 65 x 13 ( on simplifying 2 and 130)
=845 sq. cm
= 1/2 x (130) x 13
=1 x 65 x 13 ( on simplifying 2 and 130)
=845 sq. cm
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