Question

find the area of a Trapezium whose parallel sides are 57 cm and 33 cm and the distance between them is 13 cm

Answer 1

Here's your answer!!

________________________

The length of parallel sides are 57cm and 33 cm.

And distance between the parallel side (height)=13 cm.

We know that,

Area of Trapezium =

$= > \frac{1}{2} \times (sum \: of \: parallel \: side ) \times height$

$= > \frac{1}{2} \times (57 + 33) \times 13$

$= > \frac{1}{2} \times 90 \times 13$

$= > 585$

Hence,

Area of this Trapezium=

$= > 585 \: {cm}^{2}$

________________________________

Hope it helps you!! :)

Answer 2

Since,

The figure is a trapezium.

and, one parallel side = 57 cm

other parallel side = 33 cm

distance between the parallel sides ( height ) = 13 cm

$\therefore$ area of a trapezium,

= $\frac{1}{2}$ × (sum of parallel sides) × height

= $\frac{1}{2}$ × ( 57 + 33 ) × 13

= $\frac{1}{\cancel{2}}$ × $\cancel{90}$ × 13

then, we will divide 90 by 2 , as 90 ÷ 2 = 45, and then we will multiply 45 and 13.

= 45 × 13

= 585 cm² (Answer) .