Question

find the area of a trapezium whose parallel sides are 6cm and 11cm and has a area 34cm .find the height of the trapezium​

Answer 1

Correct Question:-

The length of a parallel sides are 6 cm and 11 cm and has an area of 34 cm . Then find the height of the trapezium .

To Find:-

• Find the height of the Trapezium.

Given:-

• The length of a parallel sides are 6 cm and 11 cm and has an area of 34 cm.

Solution:-

$\tt\implies \: Area \: \: of \: \: trapezium = \dfrac { 1 } { 2 } \times ( a + b ) \times h$

$\tt\implies \: 34 = \dfrac { 1 } { 2 } \times ( 6 + 11 ) \: h$

$\tt\implies \: 34 = \dfrac { 1 } { 2 } \times 17h$

$\tt\implies \: 17h = 34 \times 2$

$\tt\implies \: 17h = \cancel\dfrac { 34 \times 2 } { 17 }$

$\tt\implies \: h = 4 \: cm$

Answer 2

$\huge \mathfrak{ \blue{ \underline{Correct \: Question :}}}$

The length of a parallel sides are 6 cm and 11 cm and has an area of 34 cm. Find the height of the trapezium.

$\huge \mathfrak{ \green{ \underline{Solution : }}}$

${ \boxed{ \purple{{\rm\implies \: Area \: \: of \: \: trapezium = \dfrac { 1 } { 2 } \times ( a + b ) \times h }}}}$

$\sf\implies \: 34 = \dfrac { 1 } { 2 } \times ( 6 + 11 ) \: h \\ \sf\implies \: 34 = \dfrac { 1 } { 2 } \times 17h \\ \sf\implies \: 17h = 34 \times 2 \\ \sf\implies \: 17h = \cancel\dfrac { 34 \times 2 } { 17 } \\ {\red{\sf\implies h = 4 \: cm}}$