Math, asked by dipasha24, 2 months ago

Find the area of a trapezium whose
parallel sides are of length 58 meters and
42 meters and whose non parallel sides
are equal, each being 20 meters.

Answers

Answered by sangeethak914
2

Answer:

750 cm²

Step-by-step explanation:

A formula for the area of a trapezium is A=12h(b1+b2)

From the given information, the trapezium is isosceles. If two heights are constructed from the endpoints of the shorter base (parallel sides), then a rectangle is constructed. The two triangles on the sides of the rectangle are congruent right triangles (this allows us to find the length of 8 [ 58−422=8 ]). Now we have two side lengths of a right triangle, so the Pythagorean Theorem can be used to find the missing side length (the height of the trapezium). 172=h2+82, h = 15.

A=12(15)(58+42)=750cm2

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