Question

Find the area of a trapezium whose parallel sides are of length 16m and 2zm and 22m and whose whose height is 12 m
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Answer 1

Answer :

Area of Trapezium is 228m²

Step-by-step Explanation :

Given : length of parallel sides of Trapezium = 16m and 22m

Height of Trapezium = 12m

To find = Area of Trapezium = ?

We know that,

Area of Trapezium = 1/2 × sum of parallel sides × height of Trapezium

Substituting the given value in above formula,

We get,

Area of Trapezium = 1/2 × ( 16 + 22 ) × 12

= 1/2 × 38 × 12

= 38 × 6

= 228 m²

Hence the Area of Trapezium is 228 m²

Answer 2

Answer:

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➜ Given:-

• Parallel sides of a Trapezium = 16m and 22m
• Height of a Trapezium = 12m

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➜ To Find:-

• Area of a Trapezium = ?

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➜ Using Formula:-

$\tiny\boxed{ \sf \: Area \: of \: a \: Trapezium \: = \: \frac{1}{2} × sum \: of \: parallel \: sides \: × \: height \: of \: a \: Trapezium }$

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➜ Calculation:-

$\boxed{ \begin{aligned}& \qquad \\ \sf \: Area \: of \: a \: Trapezium \: = \: \frac{1}{2} \times (16 + 22) \times 12 \\ \\ \sf \: \implies \: \frac{1}{2} \times 38 \times 12 \\ \\ \sf \: \implies38 \times 6 \\ \\ \boxed{ \sf \: \implies \: 228 \: m {}^{2} } \end{aligned}}$

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➜ Final Answer:-

Area of a Trapezium = 228m²

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