Question

Find the area of a trapezium whose parallel sides are of lengths 10 cm and 12 cm and distance between them is 4 cm.

Answer 1

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YOUR ANSWER...

Area of trapezium =
$\frac{1}{2} \times height(sum \: of \: parallel \: sides)$
According to the question,

$= \frac{1}{2} \times 4(10 + 12)$

$= 2 \times 22$

$= 44 {cm}^{2}$


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Answer 2

Given : a  trapezium whose parallel sides are 10 cm and 12 cm and distance between them is 4  cm

To Find : area of a  trapezium

Solution:

Area of  a trapezium  = (1/2) ( sum of parallel sides) * distance between them

=> Area of  a trapezium  = (1/2)  (10 + 12) * 4

=> Area of  a trapezium  = (1/2)  (22) * 4

=> Area of  a trapezium  = 11* 4

=> Area of  a trapezium  =  44 cm²

Area of  a trapezium  is 44 cm²

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