Question

Find the area of a trapezium whose parallel sides of lengths 10 em and 15 cm are a
distance of 6 cm from each other. Calculate this area as
li) the the sum of the areas of two triangles and one rectangle
the difference of the area of a rectangle and the sum of the areas of two triangles.​

Answer 1

Step-by-step explanation:

here is your answer

Answer 2

Step-by-step explanation:

area =1/2*sum of parallel side *distance between them =1/2*(10+15)*6=75cm sq then draw perpendicular from up on the base then there are two triangle of heights 6cm and base 2.5cm and a rectangle of l=10 and b=6