Question

Find the area of a trapezium whoselengths of parallel sides are 25 cm and 19cm and distance between the parallel sidesis 15 cm ​

Answer 1

Given :

• Length of Parallel sides of a a trapezium are 25 cm and 19 cm .
• Distance between the parallel sides is 15 cm .

To Find :

• Area of Trapezium .

Solution :

$\longmapsto\tt{Parallel\:Sides=25\:cm\:and\:19\:cm}$

As Given that Distance between the parallel sides is 15 cm . So ,

$\longmapsto\tt{Height=15\:cm}$

Using Formula :

$\longmapsto\tt\boxed{Area\:of\:Trapezium=\dfrac{1}{2}\times{(Sum\:of\:parallel\:sides)}\times{h}}$

Putting Values :

$\longmapsto\tt{\dfrac{1}{2}\times{(25+19)}\times{25}}$

$\longmapsto\tt{\dfrac{1}{{\cancel{2}}}\times{{\cancel{44}}}\times{25}}$

$\longmapsto\tt{22\times{15}}$

$\longmapsto\tt\bf{330\:{cm}^{2}}$

So , The Area of the Trapezium is 330 cm² .

Answer 2

Answer:

• 330 cm².

Step-by-step explanation:

Given :

=> First parallel side = 25 cm

=> Second parallel side = 19 cm

=> Distance between parallel sides = 15 cm

To find :

=> Area of trapezium.

Solution :

>> Area of trapezium:

=> 1/2 × (sum of parallel sides) × (distance between the parallel sides)

=> 1/2 × (25 + 19) × 15

=> 1/2 × 44 × 15

=> 22 × 15

∴ 330 cm² is the area of the trapezium.