Question

Find the area of a trapezium whoselengths of parallel sides are 25 cm and 19cm and distance between the parallel sides is 15 cm



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Answer 1

Answer:

Area of Trapezium

$= \frac{1}{2} \times (25 + 19) \times 15 \\ = \frac{1}{2} \times 44 \times 15 \\ = 22 \times 15 \\ = 330 \: {cm}^{2}$

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Answer 2

Area of trapezium = $\frac{1}{2} \times$

(sum of parallel sides )× height

height may be considered as distance between the parallel sides.

Now,

Area of trapezium = $\frac{1}{2} \times$

(25+19 )× 15

$\implies \frac{1}{2} \times$44× 15

$\implies \frac{1}{\cancel2} \times \cancel{44}$× 15

$\implies$ 22×15

$\implies 330cm^3$