Question

find the area of a trapezium with parallel sides a=102 CM, b=7.8 CM and h=a+b/3 CM. ​

Answer 1

Step-by-step explanation:

area of trapezium =1/2×(a+b)×h

1/2×(102+7.8)×(102+7.8÷3)

1/2×109.8×36.6

= 2009.34

Answer 2

GIVEN:

• Parallel sides a = 102cm and b = 7.8 cm
• Height of the trapezium = $\bf{\dfrac{a+b}{3}}$

TO FIND:

• What is the area of the trapezium ?

SOLUTION:

We have given that the parallel sides of trapezium are 102 and 7.8 cm respectively

and the height is $\bf{\dfrac{a+b}{3}}$

$\rm{ Height = \dfrac{102+7.8}{3}}$

$\rm{ Height = \cancel\dfrac{109.8}{3}}$

➠$\bf{ Height (h) = 36.6 \: cm}$

We know that the formula for finding the area of the trapezium is:-

$\bf{ Area = \dfrac{1}{2} \times (Sum \: of \: parallel \: sides) \times height}$

According to question:-

$\rm{\rightharpoonup Area = \dfrac{1}{2} \times (102+7.8) \times 36.6}$

$\rm{\rightharpoonup Area = \dfrac{1}{\cancel{2}} \times 109.8 \times \cancel{36.6}}$

$\rm{\rightharpoonup Area = 109.8 \times 18.3}$

$\bf{\rightharpoonup \star \: Area = 2009.34 \: cm^2 \: \star}$

❝ Hence, the area of trapezium is 2009.34 cm² ❞

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