Question

Find the area of a trapezoid with bases 6 and 15 and height 12

Answer 1

Answer:

$area \: of \: trapezium \: = \frac{1}{2} (a + b)h$

$a = 15$

$b = 6$

$h =12$

$area \: of \: trapezium = \frac{1}{2} (15 + 6) \times 12 = \frac{1}{2 } \times 21 \times 12 = 21 \times 6 = 126$

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