Question

FIND THE AREA OF A TRIANGLE ABC WHOSE SIDES ARE 20cm 30cm AND 80 cm​

Answer 1

Step-by-step explanation:

Formula Used:-

$\sf Herons \: Formula$

$\sf \sqrt{s(s - a)(s - b)(s - c)}$

Here:-

a,b,c are sides

S is semiperimeter which is

$\sf \: \frac{a + b + c}{2}$

Let's take:-

a = 20cm

b = 30cm

c = 80cm

Process:-

First let's find Semiperimeter first.

Semiperimeter,S = a+b+c/2( We know)

By our values taken

$\sf \: \frac{20 + 30 + 80}{2}$

$\sf \implies \frac{130}{2} = 65cm$

Let's write down values neatly:-

a = 20cm

b = 30cm

c = 80cm

S = 65cm

NOW FINDING USING HERONS FORMULA.

$\sf \: \sqrt{65(65 - 20)(65 - 30)(65 - 80)}$

$\sf \: \sqrt{65 \times 45 \times 35 \times - 15}$

But the question is wrong...

Because area can't be negative