Question

find the area of a triangle formed by (1.-4),(3,-2),(-3,16)

Answer 1

Hy friend!
For area of ∆
=1/2 [x1(y2-y3)+x2(y3-y1)+x3(y1-y2)
1/2[1(-2-16)+3(16+4)-3(-4+2)]
1/2[1(-18)+60-3(-2)]
1/2[-18+60+6]
1/2[-12+60]
1/2(48)
=48/2= 24 ans
I hope it helps u rohit


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Answer 2

Answer:

The area of triangle is 24 square units.

Step-by-step explanation:

The vertices of triangle are (1.-4),(3,-2),(-3,16).

The area of triangle is

$A=\frac{1}{2}[x_1(y_2-y_3)+x_2(y_3-y_1)+x_3(y_1-y_2)]$

$A=\frac{1}{2}[1(-2-16)+3(16-(-4))-3(-4-(-2))]$

$A=\frac{1}{2}[-18+60+6]$

$A=\frac{1}{2}[48]$

$A=24$

Therefore the area of triangle is 24 square units.