Question

Find the area of a triangle formed by the points A (3,2) B(4,7) and (7.-4)
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Answer 1

The formula for area of a triangle when points $(x_{1} ,y_{1} ),(x_{2} ,y_{2} ),(x_{3} ,y_{3} )$  are given,

$\frac{1}{2} [x_{1} (y_{2}-y_{3}  )+x_{2} (y_{3}-y_{1}  )+x_{3} (y_{1}-y_{2}  )]$

Applying it here,

$\frac{1}{2}  [3(7+4  )+4 (-4-2  )+7 (2-7  )]=\frac{1}{2}[33-24-35]=-13$

but area can't be negative so area=13 sq units

#BAL #answerwithquality

Answer 2

Ar. of ∆ = 1/2 [ x1 (y2-y3) + X2(y3-y1) +x3(y1-y2)

Step-by-step explanation:

Here , Ur Answer is in this picture

hope it's help you ✌❤

$<marquee > #BAL$ ✌

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