Find the area of a triangle formed by the points (x1 , y1) (x2 , y2) and (x3, y3)
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Area of triangle=1\2 ×[x1(y2-y3)+x2(y3-y1)+x3(y1-y2)]
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- If the Vertices of Triangle ABC are A(x₁ , y₁) , B(x₂ , y₂) , C(x₃ , y₃)
Then The Area of Triangle ABC = 1/2 × [x₁(y₂- y₃) + x₂(y₃ - y₁ ) + x₃(y₁ - y₂)]
This Concept Comes Under Co - Ordinate Geometry !!
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