find the area of a triangle having base 7cm and altitude 2 cm
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Area of the triangle = 1/2(b)(h) = 1/2(7)(2) = 7cm²
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We know area of triangle (with base and height/altitude given)=1/2×base×height/altitude
Therefore, area of ∆ABC=1/2×BC×AD sq.unit(s)
=1/2×10×7 cm²
=5×7 cm²
=35 cm²(Ans)
Hope this helps…!!
Therefore, area of ∆ABC=1/2×BC×AD sq.unit(s)
=1/2×10×7 cm²
=5×7 cm²
=35 cm²(Ans)
Hope this helps…!!
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