Math, asked by Ameena13, 7 months ago

find the area of a triangle having perimeter 32 cm. one of its side is equal to 11cm and difference of the other two is 5 cm

Answers

Answered by ronitrawat13

0

11+X+Y=32
X+Y= 21
&
X-Y = 5
X= 8 & Y= 13
So area would be 1/2 base * height

1/2 * 5 * 8 = 20

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