Find the area of a triangle having perimeter 32cm one side 11cm and difference of other two sides is 5cm
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Solutions :-
We have,
Perimeter of triangle = 32 cm
One of its side = 11 cm
Let the second side be x
And third side be x + 5
Perimeter of triangle = sum of three sides
A/q
=> 11 + x + x + 5 = 32
=> 2x = 32 - 16
=> 2x = 16
=> x = 16/2 = 8
So, second side = x = 8 cm
Third side = x + 5 = 8 + 5 = 13 cm
Now,
By using heron's formula,
Find the area of a triangle :-
Answer : Area of triangle = 43.81 cm²
We have,
Perimeter of triangle = 32 cm
One of its side = 11 cm
Let the second side be x
And third side be x + 5
Perimeter of triangle = sum of three sides
A/q
=> 11 + x + x + 5 = 32
=> 2x = 32 - 16
=> 2x = 16
=> x = 16/2 = 8
So, second side = x = 8 cm
Third side = x + 5 = 8 + 5 = 13 cm
Now,
By using heron's formula,
Find the area of a triangle :-
Answer : Area of triangle = 43.81 cm²
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